Created
October 8, 2015 21:36
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| package com.j2n.sorting; | |
| public class MyQuickSort { | |
| private int array[]; | |
| private int length; | |
| public void sort(int[] inputArr) { | |
| if (inputArr == null || inputArr.length == 0) { | |
| return; | |
| } | |
| this.array = inputArr; | |
| length = inputArr.length; | |
| quickSort(0, length - 1); | |
| } | |
| private void quickSort(int lowerIndex, int higherIndex) { | |
| int i = lowerIndex; | |
| int j = higherIndex; | |
| // calculate pivot number, I am taking pivot as middle index number | |
| int pivot = array[lowerIndex+(higherIndex-lowerIndex)/2]; | |
| // Divide into two arrays | |
| while (i <= j) { | |
| /** | |
| * In each iteration, we will identify a number from left side which | |
| * is greater then the pivot value, and also we will identify a number | |
| * from right side which is less then the pivot value. Once the search | |
| * is done, then we exchange both numbers. | |
| */ | |
| while (array[i] < pivot) { | |
| i++; | |
| } | |
| while (array[j] > pivot) { | |
| j--; | |
| } | |
| if (i <= j) { | |
| exchangeNumbers(i, j); | |
| //move index to next position on both sides | |
| i++; | |
| j--; | |
| } | |
| } | |
| // call quickSort() method recursively | |
| if (lowerIndex < j) | |
| quickSort(lowerIndex, j); | |
| if (i < higherIndex) | |
| quickSort(i, higherIndex); | |
| } | |
| private void exchangeNumbers(int i, int j) { | |
| int temp = array[i]; | |
| array[i] = array[j]; | |
| array[j] = temp; | |
| } | |
| public static void main(String a[]){ | |
| MyQuickSort sorter = new MyQuickSort(); | |
| int[] input = {24,2,45,20,56,75,2,56,99,53,12}; | |
| sorter.sort(input); | |
| for(int i:input){ | |
| System.out.print(i); | |
| System.out.print(" "); | |
| } | |
| } | |
| } |
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