Created
March 15, 2013 07:57
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Dict comprehension review
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errors = {} | |
for key, value in bundle.data.items(): | |
if not some_test(value): | |
if key not in errors: | |
errors[key] = [] | |
errors[key].append('required.') | |
# R1: использовать defaultdict | |
from collections import defaultdict | |
errors = defaultdict(list) | |
for key, value in bundle.data.items(): | |
if not some_test(value): | |
errors[key].append('required.') | |
# R2: если это нормальный словарь, то ключи повторятся не будут, | |
# а следовательно проверка на наличие не нужна | |
errors = {} | |
for key, value in bundle.data.items(): | |
if not some_test(value): | |
errors[key] = ['required.'] | |
# R3: использовать dict comprehension | |
errors = {key: ['required.'] for key, value in bundle.data.items() if not some_test(value)} | |
# R3a: можно форматировать как больше нравится | |
errors = {key: ['required.'] for key, value in bundle.data.items() | |
if not some_test(value)} | |
errors = {key: ['required.'] | |
for key, value in bundle.data.items() | |
if not some_test(value)} | |
errors = { | |
key: ['required.'] | |
for key, value in bundle.data.items() | |
if not some_test(value) | |
} | |
# R3b: python 2.6- не поддерживает dict comprehension: | |
# используем dict() + генераторное выражение | |
errors = dict((key, ['required.']) for key, value in bundle.data.items() if not some_test(value)) |
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