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@Surgo
Created January 30, 2011 14:29
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SRM492 - div2 - level one
#! /usr/bin/env python
# -*- coding: utf-8 -*-
"""SRM492 - div2 - level one
Gogo owns N wine cellars, numbered 0 through N-1. He possesses a
time machine and will use it to advance time in one of the cellars,
maturing all the wine inside. However, as a side effect, he must
also choose one other cellar and turn back time there, making
the wine inside younger.
You are given two int[]s, profit and decay.
Advancing time in cellar i will gain Gogo a profit of profit[i].
Turning back time in cellar i will lose him decay[i] in profit.
Return the maximum profit that Gogo can gain by advancing time in
one cellar and turning time back in another cellar.
It is guaranteed that this profit will be positive.
Definition:
Class: TimeTravellingCellar
Method: determineProfit
Parameters: int[], int[]
Returns: int
Method signature: int determineProfit(int[] profit, int[] decay)
"""
class TimeTravellingCellar(object):
"""Time Travelling Cellar
Constraints:
- profit will contain between 2 and 50 elements, inclusive.
- Each element of profit will be between 1 and 10000, inclusive.
- decay will contain the same number of elements as profit.
- Each element of decay will be between 1 and 10000, inclusive.
- The maximum profit that Gogo can gain will be positive.
>>> cellar = TimeTravellingCellar()
>>> print cellar.determineProfit([1,2,3, ], [3,1,2, ])
2
>>> print cellar.determineProfit([3,2, ], [1,2, ])
1
>>> print cellar.determineProfit([3,3,3, ], [1,1,1, ])
2
>>> print cellar.determineProfit([1000,500,250,125, ], [64,32,16,8, ])
992
"""
def __init__(self):
pass
def determineProfit(self, profit=[], decay=[]):
m = 0
for i in range(len(profit)):
for j in [j for j in range(len(decay)) if j != i]:
m = m < profit[i] - decay[j] and profit[i] - decay[j] or m
return m
if __name__ == '__main__':
import doctest
doctest.testmod()
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