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Surya Pratap SuryaPratapK

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class Solution {
#define ll long long
public:
long long countSubarrays(vector<int>& nums, int minK, int maxK) {
ll valid_subarrays = 0;
int invalid_idx = -1;
int minK_idx = -1;
int maxK_idx = -1;
for(int i=0;i<nums.size();++i){
class Solution {
using ll = long long;
public:
long long countSubarrays(const vector<int>& nums, long long k) {
ll n = nums.size();
ll left = 0, right = 0; // window is [left, right)
ll sum = 0; // sum of nums[left..right-1]
ll count = 0;
while (left < n) {
class Solution {
#define ll long long
public:
long long countInterestingSubarrays(vector<int>& nums, int modulo, int k) {
ll n = nums.size();
ll pos=0;
ll interesting_subarrays = 0;
ll prefix_count = 0;
unordered_map<ll,ll> mod_freq;
class Solution {
public:
int countCompleteSubarrays(vector<int>& nums) {
unordered_set<int> unique_elements(nums.begin(),nums.end());
int unique_count = unique_elements.size();
int left = 0;
int right = 0;
int n = nums.size();
unordered_map<int,int> freq;
class Solution {
vector<int> findLPS(string& patt){
int n=patt.size();
vector<int> lps(n);
int i=1;
int j=0;
while(i<n){
if(patt[i]==patt[j]){
lps[i]=j+1;
class Solution {
#define ll long long
ll count[15][10005];
ll prefix_sum[15][10005];
ll options[15];
int MOD = 1e9+7;
void countUniqueSequences(int curr,int idx,int& maxValue){
options[idx]+=1;
class Solution {
#define ll long long
public:
int numberOfArrays(vector<int>& differences, int lower, int upper) {
ll gap = 0;
ll min_val = 0;
ll max_val = 0;
ll curr_val = 0;
for(int& ele: differences){
curr_val += ele;
class Solution {
public:
int numRabbits(vector<int>& answers) {
int n = answers.size();
unordered_map<int,int> group_freq;
int count = 0;
//Insert all elements and count full_group_elements
for(int ele: answers){
if(ele==0)
class Solution {
public:
string countAndSay(int n) {
if(n==1) return "1";
string number = "1";
for(int i=2;i<=n;++i){
//Build new string
string res;
int count = 1;
class Solution {
using ll = long long;
public:
long long countGood(vector<int>& nums, int k) {
ll n = nums.size();
ll left = 0, right = 0;
ll good_subarrays = 0;
unordered_map<ll,ll> freq;
ll equal_pairs = 0;