Last active
May 30, 2021 14:00
-
-
Save THeK3nger/7169c986a87b8307396139050b1e9668 to your computer and use it in GitHub Desktop.
TypeScript BinaryHeap
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
// Original JavaScript Code from Marijn Haverbeke (http://eloquentjavascript.net/1st_edition/appendix2.html) | |
export class BinaryHeap<T> { | |
content: T[]; | |
scoreFunction: (x: T) => number; | |
constructor(scoreFunction: (x: T) => number) { | |
this.content = []; | |
this.scoreFunction = scoreFunction; | |
} | |
push(element: T) { | |
this.content.push(element); | |
this.bubbleUp(this.content.length - 1); | |
} | |
pop(): T { | |
let result = this.content[0]; | |
let end = this.content.pop(); | |
if (this.content.length > 0) { | |
this.content[0] = end; | |
this.sinkDown(0); | |
} | |
return result; | |
} | |
remove(node: T) { | |
let length = this.content.length; | |
// To remove a value, we must search through the array to find | |
// it. | |
for (var i = 0; i < length; i++) { | |
if (this.content[i] != node) continue; | |
// When it is found, the process seen in 'pop' is repeated | |
// to fill up the hole. | |
let end = this.content.pop(); | |
// If the element we popped was the one we needed to remove, | |
// we're done. | |
if (i == length - 1) break; | |
// Otherwise, we replace the removed element with the popped | |
// one, and allow it to float up or sink down as appropriate. | |
this.content[i] = end; | |
this.bubbleUp(i); | |
this.sinkDown(i); | |
break; | |
} | |
} | |
size() { | |
return this.content.length; | |
} | |
private bubbleUp(n: number) { | |
// Fetch the element that has to be moved. | |
let element = this.content[n], score = this.scoreFunction(element); | |
// When at 0, an element can not go up any further. | |
while (n > 0) { | |
// Compute the parent element's index, and fetch it. | |
let parentN = Math.floor((n + 1) / 2) - 1, | |
parent = this.content[parentN]; | |
// If the parent has a lesser score, things are in order and we | |
// are done. | |
if (score >= this.scoreFunction(parent)) | |
break; | |
// Otherwise, swap the parent with the current element and | |
// continue. | |
this.content[parentN] = element; | |
this.content[n] = parent; | |
n = parentN; | |
} | |
} | |
private sinkDown(n: number) { | |
// Look up the target element and its score. | |
var length = this.content.length, | |
element = this.content[n], | |
elemScore = this.scoreFunction(element); | |
while (true) { | |
// Compute the indices of the child elements. | |
var child2N = (n + 1) * 2, child1N = child2N - 1; | |
// This is used to store the new position of the element, | |
// if any. | |
var swap = null; | |
// If the first child exists (is inside the array)... | |
if (child1N < length) { | |
// Look it up and compute its score. | |
var child1 = this.content[child1N], | |
child1Score = this.scoreFunction(child1); | |
// If the score is less than our element's, we need to swap. | |
if (child1Score < elemScore) | |
swap = child1N; | |
} | |
// Do the same checks for the other child. | |
if (child2N < length) { | |
var child2 = this.content[child2N], | |
child2Score = this.scoreFunction(child2); | |
if (child2Score < (swap == null ? elemScore : child1Score)) | |
swap = child2N; | |
} | |
// No need to swap further, we are done. | |
if (swap == null) break; | |
// Otherwise, swap and continue. | |
this.content[n] = this.content[swap]; | |
this.content[swap] = element; | |
n = swap; | |
} | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment