Quick and Easy C# Object <> XML Serialization/Deserialization in Unity

ObjectSerialization.cs

using UnityEngine;
using System.Collections;
/// <summary>
/// Quick and easy C#<>XML (de)serialization example by @Talsidor
/// References:
/// https://stackoverflow.com/questions/4123590/serialize-an-object-to-xml
/// https://stackoverflow.com/questions/364253/how-to-deserialize-xml-document
/// </summary>
public class ObjectSerialization : MonoBehaviour 
{
	public Car[] cars;

	void Start()
	{
		// Comment in whichever of these lines you wish to happen
		//Car.Deserialize("cars");
		Car.Serialize("cars");

		// Publicly visible in the Unity inspector so you can see the contents of the Car.cars array
		cars = Car.cars;
	}
}

[System.Serializable]
public class Car 
{
	public static Car[] cars;

	// The information contained in one instance of this class
	public string make;
	public string model;
	public int year;

	/// <summary>
	/// Turns the 'cars' array into an XML file with the specified filename
	/// </summary>
	/// <param name="fileName">Adds dataPath and extension automatically</param>
	public static void Serialize (string fileName) 
	{
		// Populate with example data so we have something to serialize
		cars = new Car[] {
				new Car() { make = "Toyota",		model = "Prius",	year = 2013 },
				new Car() { make = "Mitsubishi",	model = "iMiev",	year = 2012 },
				new Car() { make = "Tesla",			model = "Model S",	year = 2014 }
			};

		using (var writer = new System.IO.StreamWriter(Application.dataPath + "/" + fileName + ".xml"))
		{
			var serializer = new System.Xml.Serialization.XmlSerializer(typeof(Car[]));
			serializer.Serialize(writer, cars);
		}
	}

	/// <summary>
	/// Retrives the specified file and populates the 'cars' array with it's contents
	/// </summary>
	/// <param name="fileName">Adds dataPath and extension automatically</param>
	public static void Deserialize(string fileName) 
	{
		using (var stream = System.IO.File.OpenRead(Application.dataPath + "/" + fileName + ".xml"))
		{
			var serializer = new System.Xml.Serialization.XmlSerializer(typeof(Car[]));
			cars = serializer.Deserialize(stream) as Car[];
		}
	}
}

Creates an XML file that looks like:

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfCar xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Car>
    <make>Toyota</make>
    <model>Prius</model>
    <year>2013</year>
  </Car>
  <Car>
    <make>Mitsubishi</make>
    <model>iMiev</model>
    <year>2012</year>
  </Car>
  <Car>
    <make>Tesla</make>
    <model>Model S</model>
    <year>2014</year>
  </Car>
  <Car>
    <make>Nissan</make>
    <model>Leaf</model>
    <year>2015</year>
  </Car>
</ArrayOfCar>