iOS repl.it - Variables Challenge Solution

variables.swift

var a = 5
var b = 8

var c = a
a = b
b = c

print("a: \(a)")
print("b: \(b)")

My solution:

`func exercise() {

var a = 5
var b = 8

let c = a
a = b
b = c

print("a: \(a)")
print("b: \(b)")

}`

func exercise() {

var a = 5
var b = 8

var c = a
a = b
b = c

print("a: \(a)")
print("b: \(b)")

}

also nice to know how to do it without a 3rd variable:

a=a+b
b=a-b
a=a-b

This would not work for strings now. Would it?

var a = 1
var b = 2
var c = a
a = b
b = c
print("a: (a)")
print("b: (b)")

var a = 7
var b = 9
var c = a
b = a
a = b
print("a is = (a)")
print ("b is = (b)")

var a = 7
var b = 8
var c = a
a = b
b = c

func exercise() {

var a = 5
var b = 8

//Write your code here. 
//Dont change any of the existing code.


print("a: \(b)")
print("b: \(a)")

}

it is working:))

var a = 5
var b = 7

a = a + b // 12
b = a - b // 12 - 7 = 5
a = a - b // 12 - 5 = 7

print("a: (a)")
print("b: (b)")

var a = 5
var b = 8

print("the value of a is (a)")
print("the valu of b is (b)")

var temp = a
a = b
b = temp

print("the value of a is (a)")
print("the valu of b is (b)")