Created
April 27, 2012 12:59
-
-
Save TryJSIL/2508997 to your computer and use it in GitHub Desktop.
Tree Benchmark
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
/* The Computer Language Benchmarks Game | |
http://shootout.alioth.debian.org/ | |
contributed by Marek Safar | |
*/ | |
using System; | |
public static class Program { | |
const int minDepth = 4; | |
public static void Main () { | |
int n = 0; | |
int maxDepth = Math.Max(minDepth + 2, n); | |
int stretchDepth = maxDepth + 1; | |
int check = (TreeNode.bottomUpTree(0, stretchDepth)).itemCheck(); | |
Console.WriteLine("stretch tree of depth {0}\t check: {1}", stretchDepth, check); | |
TreeNode longLivedTree = TreeNode.bottomUpTree(0, maxDepth); | |
for (int depth = minDepth; depth <= maxDepth; depth += 2) { | |
int iterations = 1 << (maxDepth - depth + minDepth); | |
check = 0; | |
for (int i = 1; i <= iterations; i++) { | |
check += (TreeNode.bottomUpTree(i, depth)).itemCheck(); | |
check += (TreeNode.bottomUpTree(-i, depth)).itemCheck(); | |
} | |
Console.WriteLine("{0}\t trees of depth {1}\t check: {2}", | |
iterations * 2, depth, check); | |
} | |
Console.WriteLine("long lived tree of depth {0}\t check: {1}", | |
maxDepth, longLivedTree.itemCheck()); | |
} | |
struct TreeNode { | |
class Next { | |
public TreeNode left, right; | |
} | |
private Next next; | |
private int item; | |
internal static TreeNode bottomUpTree (int item, int depth) { | |
if (depth > 0) { | |
return new TreeNode( | |
new Next { | |
left = bottomUpTree(2 * item - 1, depth - 1), | |
right = bottomUpTree(2 * item, depth - 1) | |
}, item | |
); | |
} else { | |
return new TreeNode(null, item); | |
} | |
} | |
TreeNode (Next next, int item) { | |
this.next = next; | |
this.item = item; | |
} | |
internal int itemCheck () { | |
// if necessary deallocate here | |
if (next == null) return item; | |
else return item + next.left.itemCheck() - next.right.itemCheck(); | |
} | |
} | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment