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August 29, 2015 14:04
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Lets you print any number of strings with any colors in one function call. Way less cumbersome then constantly switching colors.
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/// <summary> | |
/// Lets you print stuff. Any number of objects. | |
/// To change forground color, pass one console color and then another object (ie: print(ConsoleColor.Red, "this will be red")). | |
/// To change both fore and back colors, path two console colors then another object (ie: print(ConsoleColor.Red, ConsoleColor.White, "this will be red on white")). | |
/// </summary> | |
/// <param name="stuff">Console colors, and objects to print.</param> | |
public static void PrintLine() { PrintLine(null); } | |
public static void PrintLine(params object[] stuff) { Print(stuff); Console.WriteLine(); } | |
public static void Print(params object[] stuff) { | |
if (stuff == null) { | |
Console.WriteLine(); | |
return; | |
} | |
ConsoleColor oldf = Console.ForegroundColor; | |
ConsoleColor oldb = Console.BackgroundColor; | |
var enumerator = stuff.GetEnumerator(); | |
while (enumerator.MoveNext()) { | |
Object o = enumerator.Current; | |
if (o is ConsoleColor) { | |
Console.ForegroundColor = ((ConsoleColor)o); | |
enumerator.MoveNext(); | |
if (enumerator.Current is ConsoleColor) { | |
Console.BackgroundColor = ((ConsoleColor)enumerator.Current); | |
enumerator.MoveNext(); | |
} | |
Console.Write(enumerator.Current.ToString()); | |
} else | |
Console.Write(enumerator.Current.ToString()); | |
Console.ForegroundColor = oldf; | |
Console.BackgroundColor = oldb; | |
} | |
} |
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