regex-text-replacer.rpy

init -1 python:
    DICTIONARY = {
        r'\bfoot\b': 'paw',
        r'\bfeet\b': 'paws'
    }

    # Python 2.7 has unordered dictionaries, convert to list instead
    keys = list(DICTIONARY.keys())

    import re
    regex_parts = []
    for i, k in enumerate(keys):
        regex_parts.append("(?P<k{0}>{1})".format(i, k))
    regex = re.compile("|".join(regex_parts), re.IGNORECASE)

    def match(m):
        key = keys[int(m.lastgroup[1:])]
        origword = m.group(0)
        replacement = DICTIONARY[key]
        if origword.isupper():
            return replacement.upper()
        if origword.islower():
            return replacement.lower()
        if origword.istitle():
            return replacement.title()
        return replacement

    from renpy.text.text import Text
    orig_init = Text.__init__
    def patch(self, text, *args, **kwargs):
        orig_init(self, regex.sub(match, text), *args, **kwargs)
    Text.__init__ = patch