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Lazy Fibonacci in Prolog
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?- fibs(F), take(F, 20, _). | |
F = [0, 1, 1, 2, 3, 5, 8, 13, 21|...], | |
freeze(_G2395, zip_with(plus, [2584, 4181|_G2395], [4181|_G2395], _G2395)). |
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zip_with(_, [], []). | |
zip_with(Goal, [A|As], [B|Bs], [C|Cs]) :- | |
call(Goal, A, B, C), | |
freeze(Cs, zip_with(Goal, As, Bs, Cs)). | |
% implementation from SWI pack list_util | |
take([], N, []) :- | |
N > 0, | |
!. | |
take(_, 0, []) :- | |
!. | |
take([H|T], N1, [H|Rest]) :- | |
N1 > 0, | |
succ(N0, N1), | |
take(T, N0, Rest). | |
% infinite, lazy Fibonacci sequence | |
fibs([0,1|T]) :- | |
F = [0,1|T], | |
F1 = [1|T], | |
freeze(T, zip_with(plus, F, F1, T)). |
Haskell:
fib = 0:1:ffib fib where ffib (a: y@(b:_)) = (a+b):ffib y
Prolog, exactly like that: -- -- -- -- -- this all started from http://stackoverflow.com/a/14514298 Jan 25 at 2:16 by mndrix
fib(X):- X=[0,1|Z], ffib(X,Z).
ffib([A|Y],Z):- Y=[B|_], N is A+B, freeze(Z, (Z=[N|W],ffib(Y,W)) ).
Test:
30 ?- fib(X), length(R,7),append(R,_,X).
X = [0, 1, 1, 2, 3, 5, 8|_G1495],
R = [0, 1, 1, 2, 3, 5, 8],
freeze(_G1495, (_G1495=[13|_G1540], ffib([8|_G1495], _G1540))).
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Thank you very much! Here's my take on it:
Seems to work too:
This a translation of