Parse arbitrary number of keyword arguments

kwarg-nargs.py

#!/usr/bin/env python3
import argparse

def parse_args():
    usage = 'kwarg-nargs.py [-h] [pos_args ...] [-dict_args [value] ... ] ...'
    
    parser = argparse.ArgumentParser(add_help=False)

    parser.add_argument('pos_args', nargs='*')

    #args, list_kwargs = parser.parse_known_args('asdf asdg --few wegew ewgew --wewg'.split())
    args, list_kwargs = parser.parse_known_args()

    pos_args = args.pos_args

    parser_kwargs = argparse.ArgumentParser(
        usage=usage,
        description='positional arguments:\n  pos_args',
        formatter_class=argparse.RawDescriptionHelpFormatter,
    )
    
    for arg in list_kwargs:
        if arg[0] == '-':
            if arg != '-h' and arg != '--help':
                parser_kwargs.add_argument(arg, nargs='*')
    args2 = parser_kwargs.parse_args(list_kwargs)

    dict_args = vars(args2)

    for key, value in dict_args.items():
        if len(value) == 0:
            dict_args[key] = None
        elif len(value) == 1:
            dict_args[key] = value[0]

    return pos_args, dict_args

pos_args, dict_args = parse_args()

def test__parse_args(*pos_args, **dict_args):
    print(pos_args)
    print(dict_args)

test__parse_args(*pos_args, **dict_args)