WitherOrNot

from __future__ import division
import pygame
import sys
import os

pygame.init()
scr = pygame.display.set_mode((200,200))

psx = -2
psy = -2

WitherOrNot

from __future__ import division
import pygame
import sys
import os
import math

pygame.init()
scr = pygame.display.set_mode((200,200))

psx = -2

WitherOrNot

import turtle
import random

t = turtle.Turtle()
s = turtle.Screen()

n = 30 # width of board, in cells, must be even
width = 10 # width of cell, in turtle units
dot_size = 0 # dot size

WitherOrNot

#!/usr/bin/env python

from selenium import webdriver
from selenium.webdriver.firefox.options import Options
import timeit
import psutil
import proxyscrape
import requests

CHW_URL = "https://www.channel-watcher.com/supplier/520/witherornot"  # Change this to your syndicate url

WitherOrNot

@echo off
cls
:a
for /f "delims=" %%i in ('adb shell pwd') do set pwd=%%i
title adbshell- %pwd%
set /p com="adbshell- %pwd% $ "
echo %com% >com.txt
goto b
:c
adb shell "%com%"

WitherOrNot

o=w=0;s=" ";b=[s]*9
while 1:
 print"\n".join(["".join(b[x:x+3])for x in 0,3,6])
 if w:break
 h=~-input();z=b[h]==s;b[h]=[b[h],"XO"[o]][z];o=[o,2+~o][z]
 for i in range(8):
	e,f,g=map(int,`0x341a4a6fa990a9ee254e`[i*3:][:3]);w|=(b[e]==b[f]==b[g]!=s)

WitherOrNot

from PIL import Image, ImageChops
import sys

img = Image.open(sys.argv[1]).convert("RGB")
w, h = img.size
out = Image.new("RGB", (w, h))

def f(x, y):
    return ((2*x+y) % w, (x+y) % h)

WitherOrNot

Keybase proof

I hereby claim:

• I am witherornot on github.
• I am witherornot (https://keybase.io/witherornot) on keybase.
• I have a public key whose fingerprint is 5378 364C 6FD6 1144 9D6E 7764 19F9 47B0 EFCC E2B6

To claim this, I am signing this object:

WitherOrNot

import numpy as np
import cv2
import matplotlib.pyplot as plt
import code
import time
import sys
from fractions import Fraction

SKIP = 8 if len(sys.argv) <= 3 else int(sys.argv[3])

WitherOrNot

?start: arrow

?arrow: operator
    | arrow "->" operator -> conditional
    | arrow "<>" operator -> biconditional

?operator: atom
    | operator "^" atom -> conjunction
    | operator "v" atom -> disjunction