Created
February 22, 2015 03:32
-
-
Save Wizmann/ea1cf898f1bcee7c9af9 to your computer and use it in GitHub Desktop.
continental divider.cc
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
#include <cstdio> | |
#include <cstdlib> | |
#include <cstring> | |
#include <iostream> | |
#include <algorithm> | |
#include <vector> | |
using namespace std; | |
#define input(x) cin >> x | |
#define print(x) cout << x << endl | |
const int SIZE = 512; | |
const int mx[] = {0, 1, 0, -1}; | |
const int my[] = {-1, 0, 1, 0}; | |
int n, sea_cnt; | |
char g[SIZE][SIZE]; | |
int nr[SIZE][SIZE]; | |
int cnc[SIZE][SIZE]; | |
void find_sea(int y, int x) { | |
if (g[y][x] != '0') { | |
return; | |
} | |
nr[y][x] = sea_cnt; | |
for (int i = 0; i < 4; i++) { | |
int ny = y + my[i]; | |
int nx = x + mx[i]; | |
if (ny >= 0 && ny < n && nx >= 0 && nx < n) { | |
find_sea(ny, nx); | |
} | |
} | |
} | |
int dfs(int y, int x) { | |
if (cnc[y][x] != -1) { | |
return cnc[y][x]; | |
} | |
cnc[y][x] = 0; | |
// if this node is a part of a sea | |
if (nr[y][x] != -1) { | |
cnc[y][x] |= (1 << nr[y][x]); | |
return cnc[y][x]; | |
} | |
for (int i = 0; i < 4; i++) { | |
int ny = y + my[i]; | |
int nx = x + mx[i]; | |
if (ny >= 0 && ny < n && nx >= 0 && nx < n && g[y][x] > g[ny][nx]) { | |
cnc[y][x] |= dfs(ny, nx); | |
} | |
} | |
return cnc[y][x]; | |
} | |
int main() { | |
sea_cnt = 0; | |
input(n); | |
for (int i = 0; i < n; i++) { | |
for (int j = 0; j < n; j++) { | |
int u; | |
scanf("%d", &u); | |
g[i][j] = u + '0'; | |
} | |
} | |
memset(nr, -1, sizeof(nr)); | |
for (int i = 0; i < n; i++) { | |
for (int j = 0; j < n; j++) { | |
if (g[i][j] != '0' || nr[i][j] != -1) { | |
continue; | |
} | |
find_sea(i, j); | |
sea_cnt++; | |
} | |
} | |
memset(cnc, -1, sizeof(cnc)); | |
for (int i = 0; i < n; i++) { | |
for (int j = 0; j < n; j++) { | |
if (cnc[i][j] != -1) { | |
continue; | |
} | |
dfs(i, j); | |
} | |
} | |
for (int i = 0; i < n; i++) { | |
for (int j = 0; j < n; j++) { | |
if (cnc[i][j] == (1 << sea_cnt) -1) { | |
printf("<%d, %d>\n", i, j); | |
} | |
} | |
} | |
return 0; | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment