multipleObjectsValuesReduce

multipleObjectsValuesReduce.js

const arr1 = [
    { val1_1: 1, val1_2: 2, val1_3: 3, val1_4: 4 },
    { val1_5: 5, val1_6: 6, val1_7: 7, val1_8: 8 }
];

const arr2 = [
    { val2_1: 1, val2_2: 2, val2_3: 3, val2_4: 4 },
    { val2_5: 5, val2_6: 6, val2_7: 7, val2_8: 8 }
].reverse();

const arr3 = [
    { val2_1: 1, val2_2: 2, val2_3: 3, val2_4: 4 },
    { val2_5: 5, val2_6: 6, val2_7: 7, val2_8: 8 }
];

const arr4 = [
    { val2_1: 1, val2_2: 2, val2_3: 3, val2_4: 4 },
    { val2_5: 5, val2_6: 6, val2_7: 7, val2_8: 8 }
];

const times = (x, y) => x * y
const plus = (x, y) => x + y
const flattenObj = (arr) => [].concat(...arr.map(obj => Object.values(obj)))
const getOnlyObjectValues = (...objArr) => objArr.map(obj => flattenObj(obj))
const timesAll = (acc, cur) => acc.map((num, index) => times(cur[index] ,num))

const process = (...objArr) => {
    
    const solve = getOnlyObjectValues(...objArr).reduce(timesAll)
                  .reduce(plus)

    return solve
}

const calc = process(arr1, arr2, arr3)
console.log(calc)