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August 13, 2022 17:46
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Rename filenames in directory structure based on their folder index
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import os | |
import re | |
# file rename example: | |
# sub-directory: "1. Introduction" | |
# files: "1. foo", "2. bar", ... => "1.1 foo", "1.2 bar", ... | |
path = '.' | |
for root, dirs, files in os.walk(path): | |
for file_name in files: | |
file_path = os.path.join(root, file_name) | |
print(file_path) | |
index_regex = re.compile(r'\/(\d+)\.') | |
if re.search(index_regex, file_path): | |
file_index = re.search(index_regex, file_path).group(1) | |
new_file_path = os.path.join(root, file_index + '.' + file_name) | |
print(new_file_path) | |
os.rename(file_path, new_file_path) | |
print() |
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