Challenge 153 - Father and Son Ages

challenge_153.md

Challenge 153 - Father and Son Ages

Create a function that takes two arguments: a father's current age and his son's current age. Сalculate how many years ago the father was twice as old as his son, or in how many years he will be twice as old.

Examples

age_difference(36, 7) ➞ 22
# 22 years from now, the father will be 58 years old and his son will be 29 years old.

age_difference(55, 30) ➞ 5
# 5 years ago, the father was 50 years old and his son was 25 years old.

age_difference(42, 21) ➞ 0

challenge_tests.py

import unittest


def find_twice_age(fathers_age: int, sons_age: int) -> int:
    return 0  # Put your code here!!!


class Test(unittest.TestCase):
    def test_1(self):
        self.assertEqual(find_twice_age(36, 7), 22)

    def test_2(self):
        self.assertEqual(find_twice_age(55, 30), 5)

    def test_3(self):
        self.assertEqual(find_twice_age(42, 21), 0)

    def test_4(self):
        self.assertEqual(find_twice_age(22, 1), 20)

    def test_5(self):
        self.assertEqual(find_twice_age(29, 0), 29)


if __name__ == "__main__":
    unittest.main()

credits.md

Found on Edabit: Father and Son Ages