Challenge 146 - Compare by ASCII Codes

challenge_146.md

Challenge 146 - Compare by ASCII Codes

Create a function that compares two words based on the sum of their ASCII codes and returns the word with the smaller ASCII sum.

Examples

ascii_compare("hey", "man") ➞ "man"
# ["h", "e", "y"] ➞ sum([104, 101, 121]) ➞ 326
# ["m", "a", "n"] ➞ sum([109, 97, 110]) ➞ 316

ascii_compare("majorly", "then") ➞ "then"

ascii_compare("victory", "careless") ➞ "victory"

Notes

• Both words will have strictly different ASCII sums.
• You can get the ASCII code for a single character using the ord function.

challenge_tests.py

import unittest


def ascii_compare(word_a: str, word_b: str) -> str:
    return ""  # Put your code here!!!


class Test(unittest.TestCase):
    def test_1(self):
        self.assertEqual("man", ascii_compare("hey", "man"))

    def test_2(self):
        self.assertEqual("then", ascii_compare("majorly", "then"))

    def test_3(self):
        self.assertEqual("magic", ascii_compare("magic", "kingdom"))

    def test_4(self):
        self.assertEqual("bored", ascii_compare("bored", "shampoo"))

    def test_5(self):
        self.assertEqual("victory", ascii_compare("victory", "careless"))


if __name__ == "__main__":
    unittest.main()

credits.md

Found on Edabit: Compare by ASCII Codes