Challenge 159 - Face Interval

challenge_159.md

Challenge 159 - Face Interval

In mathematics, interval is the difference between the largest number and the smallest number in a list.

To illustrate:

A = (3, 5, 7, 23, 11, 42, 80)

Interval of A = 80 - 3 = 77

Create a function that takes a list and returns ":)" if the interval of the list is equal to any other element; otherwise return ":(".

Examples

face_interval([1, 2, 5, 8, 3, 9]) ➞ ":)"
# List interval is equal to one of the other elements.

face_interval([5, 2, 8, 3, 11]) ➞ ":("
# List interval is not among the other elements.

Notes

• Lists won't contain any duplicate numbers.

challenge_tests.py

from __future__ import annotations
import unittest


def face_interval(numbers: list[int]) -> str:
    return ""  # Put your code here!!!


class Test(unittest.TestCase):
    def test_1(self):
        self.assertEqual(face_interval([1, 2, 5, 8, 3, 9]), ":)")

    def test_2(self):
        self.assertEqual(face_interval([5, 2, 6, 3, 11]), ":(")

    def test_3(self):
        self.assertEqual(face_interval([20, 50, 13, 60, 79, 72, 99]), ":(")

    def test_4(self):
        self.assertEqual(face_interval([11, 42, 83, 28, 47, 94]), ":)")


if __name__ == "__main__":
    unittest.main()

credits.md

Found on Edabit: Face Interval