Challenge 134 - Card Counting (BlackJack)

challenge_134.md

Challenge 134 - Card Counting (BlackJack)

In BlackJack, cards are counted with -1, 0, 1 values:

• 2, 3, 4, 5, 6 are counted as +1
• 7, 8, 9 are counted as 0
• 10, J, Q, K, A are counted as -1

Create a function that counts the number and returns it from the list of cards provided.

Examples

count([5, 9, 10, 3, "J", "A", 4, 8, 5]) ➞ 1

count(["A", "A", "K", "Q", "Q", "J"]) ➞ -6

count(["A", 5, 5, 2, 6, 2, 3, 8, 9, 7]) ➞ 5

Notes

• String inputs will always be upper case.
• You do not need to consider case sensitivity.
• If the argument is empty, return 0.
• There will be no input other than: 2, 3, 4, 5, 6, 7, 8, 9, 10, "J", "Q", "K", "A".

challenge_tests.py

from __future__ import annotations
from typing import List, Union
import unittest


Card = Union[int, str]


def count(cards: list[Card]) -> int:
    return 0  # Put your code here!!!


class Test(unittest.TestCase):
    def test_1(self):
        self.assertEqual(1, count([5, 9, 10, 3, 'J', 'A', 4, 8, 5]))

    def test_2(self):
        self.assertEqual(-6, count(['A', 'A', 'K', 'Q', 'Q', 'J']))

    def test_3(self):
        self.assertEqual(5, count(['A', 5, 5, 2, 6, 2, 3, 8, 9, 7]))

    def test_4(self):
        self.assertEqual(8, count([2, 2, 2, 2, 2, 2, 2, 2]))

    def test_5(self):
        self.assertEqual(0, count([]))

    def test_6(self):
        self.assertEqual(-7, count(['A', 'A', 'A', 'A', 'A', 'A', 'A']))

    def test_7(self):
        self.assertEqual(0, count(['A', 'K', 'Q', 'J', 10, 9, 8, 7, 6, 5, 4, 3, 2]))


if __name__ == "__main__":
    unittest.main()

credits.md

Found on Edabit: Card Counting (BlackJack)