Challenge 137 - Even or Odd Number of Factors

challenge_137.md

Challenge 137 - Even or Odd Number of Factors

Create a function that returns "even" if a number has an even number of factors and "odd" if a number has an odd number of factors.

Examples

factor_group(33) ➞ "even"

factor_group(36) ➞ "odd"

factor_group(7) ➞ "even"

Notes

• You don't need to actually calculate the factors to solve this problem.
• Think about why a number would have an odd number of factors.

challenge_tests.py

import unittest


def factor_group(num: int) -> str:
    return ""  # Put your code here!!!


class Test(unittest.TestCase):
    def test_1(self):
        self.assertEqual("even", factor_group(33))

    def test_2(self):
        self.assertEqual("odd", factor_group(36))

    def test_3(self):
        self.assertEqual("even", factor_group(7))

    def test_4(self):
        self.assertEqual("odd", factor_group(1))

    def test_5(self):
        self.assertEqual("even", factor_group(19))

    def test_6(self):
        self.assertEqual("even", factor_group(27))

    def test_7(self):
        self.assertEqual("odd", factor_group(100))

    def test_8(self):
        self.assertEqual("even", factor_group(18))

    def test_9(self):
        self.assertEqual("odd", factor_group(16))


if __name__ == "__main__":
    unittest.main()

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