Compute 1+2+3+4+5 in C without using if and while

there_is_no_need_for_if_and_while_in.c

//Inspired by http://www.zhihu.com/question/20125963/answer/18158192 (chinese)
#include<stdio.h>
#include<stdlib.h>
#define MAXN 5
typedef void* (*loop_func)(void* params);
typedef void (*branch)(loop_func,void*);
void conditionFalse(loop_func loopfunc,void* params){
    (*loopfunc)(params);
}
void conditionTrue(loop_func loopfunc,void* params){
    int* pi = (int*)params;
    char* pch = (char*)(pi+1);
    int* psum = (int*)(pch+1);
    printf("i=%d,ch=%c,sum=%d\n",*pi,*pch,*psum);
    free(params);
}
void* loop(void* params){
    int* pi = (int*)params;
    char* pch = (char*)(pi+1);
    int* psum = (int*)(pch+1);
    (*pi)++;
    (*psum)+=(*pi);
    (*pch)++;
    branch* branches;
    branches = (branch*)malloc(sizeof(branch)*2);
    branches[0] = &conditionFalse;
    branches[1] = &conditionTrue;
    (*branches[((*pi)==MAXN)%2])(&loop,params);
    free(branches);
}
int main(int argc,char** argv){
    void* params = malloc(sizeof(int)*2+sizeof(char));
    int* pi = (int*)params;
    char* pch = (char*)(pi+1);
    int* psum = (int*)(pch+1);
    (*pi) = 0;
    (*pch) = 'A';
    (*psum) = 0;
    loop(params);
    return 0;
}