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Python implementation of Banker's algorithm, written in Python 3
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def main(): | |
processes = int(input("number of processes : ")) | |
resources = int(input("number of resources : ")) | |
max_resources = [int(i) for i in input("maximum resources : ").split()] | |
print("\n-- allocated resources for each process --") | |
currently_allocated = [[int(i) for i in input(f"process {j + 1} : ").split()] for j in range(processes)] | |
print("\n-- maximum resources for each process --") | |
max_need = [[int(i) for i in input(f"process {j + 1} : ").split()] for j in range(processes)] | |
allocated = [0] * resources | |
for i in range(processes): | |
for j in range(resources): | |
allocated[j] += currently_allocated[i][j] | |
print(f"\ntotal allocated resources : {allocated}") | |
available = [max_resources[i] - allocated[i] for i in range(resources)] | |
print(f"total available resources : {available}\n") | |
running = [True] * processes | |
count = processes | |
while count != 0: | |
safe = False | |
for i in range(processes): | |
if running[i]: | |
executing = True | |
for j in range(resources): | |
if max_need[i][j] - currently_allocated[i][j] > available[j]: | |
executing = False | |
break | |
if executing: | |
print(f"process {i + 1} is executing") | |
running[i] = False | |
count -= 1 | |
safe = True | |
for j in range(resources): | |
available[j] += currently_allocated[i][j] | |
break | |
if not safe: | |
print("the processes are in an unsafe state.") | |
break | |
print(f"the process is in a safe state.\navailable resources : {available}\n") | |
if __name__ == '__main__': | |
main() |
nice code but too complex to understand.
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@BILWANATH-2002 Hey! actually, i don't have time to do it, it's all here, just change it as you need. ;)