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abdollar/Haskell

Created December 8, 2011 22:16
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Add all the natural numbers below one thousand that are multiples of 3 or 5.
Raw
Haskell
sum [n | n <- [3..999], n `mod` 5 == 0 || n `mod` 3 == 0]
Raw
Ruby
(3..999).find_all{|n| (n % 3 == 0) || (n % 5 == 0) }.inject{|sum,x| sum + x }
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(3..999).select{|n| (n % 3 == 0) || (n % 5 == 0) }.inject(:+)

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