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# O(n) time | O(d) space | |
def invertBinaryTree(tree): | |
if tree is None: | |
return 0 | |
(tree.left, tree.right) = (tree.right, tree.left) | |
if tree.left: | |
invertBinaryTree(tree.left) | |
if tree.right: | |
invertBinaryTree(tree.right) | |
# O(n) time | O(n) space | |
def invertBinaryTree(tree): | |
queue = [tree] | |
while len(queue): | |
current = queue.pop(0) | |
if current is None: | |
continue | |
tree.left, tree.right = tree.right, tree.left | |
queue.append(current.left) | |
queue.append(current.right) | |
def isSameTree(self, p, q): | |
if p or q is None: | |
return False | |
if p and q is None: | |
return True | |
if p != q: | |
return False | |
self.isSameTree(p.left, q.left) | |
self.isSameTree(p.right, q.right) | |
def isSymmetric(self, root): | |
if root is None: | |
return 0 | |
return self._isSymmetric(root.left, root.right) | |
def _isSymmetric(self, left, root): | |
if left or right is None: | |
return False | |
if left and right is None: | |
return True | |
if left.val == right.val: | |
isSameChildNode1 = self._isSymmetric(left.left, right.right) | |
isSameChildNode2 = self._isSymmetric(left.right, right.left) | |
else: | |
return False | |
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