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The fastest way to compute the MSD of a huge set of atoms using Python: Scipy.weave + basic compiler optimization + openmp + clean memory access patterns.
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#!/usr/bin/python | |
from scipy import weave | |
from scipy.weave import converters | |
from numpy import * | |
#Yeah that's right stick your code in a fucking comment cause its a weave hack. | |
msdCode = """ | |
double c,d; | |
double *seta,*setb; | |
int dt; | |
#pragma omp parallel for default(shared) private(dt,c) | |
for( dt=1; dt<Ntime; dt++){ | |
c=0.0; | |
for( int i=0; i<Ntime-dt; i++){ //average over all time steps to smooth things out | |
seta = &(atoms[i*Natom*3]); | |
setb = &(atoms[(i+dt)*Natom*3]); | |
for( int j=0; j<Natom; j++){ | |
for( int dof=0; dof<3; dof++){ //Degrees of Freedom | |
d = seta[j*3+dof] - setb[j*3+dof]; | |
if( d > lengths[dof]/2.0 ) d -= lengths[dof]; //Lower PBC | |
if( d <-lengths[dof]/2.0 ) d += lengths[dof]; //Upper PBC | |
c += d*d; | |
} | |
} | |
} | |
msd[dt-1] = c/(Natom*(Ntime-dt)); | |
} | |
""" | |
#Calculates the MSD enforcing periodic boundary conditions | |
def meanSquareDist(atoms,Natom,Ntime,lengths): | |
atoms = array(atoms).ravel() #atoms is an Ntime x Natom x 3 array... now flattened | |
delT = array(range(1,Ntime+1)) | |
msd = zeros(Ntime) | |
compiler_args = ['-march=native -O3 -fopenmp'] | |
headers = r"""#include <omp.h>""" | |
libs = ['gomp'] | |
weave.inline(msdCode,['atoms','Ntime','Natom','lengths','msd'],\ | |
extra_compile_args=compiler_args,\ | |
support_code=headers,\ | |
libraries=libs) | |
return delT,msd |
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