Calculate Pi using acceptance-rejection

calculate_pi

# -*- coding: utf-8 -*-
"""
Created on Sun Oct  4 17:31:12 2020

@author: Localuser
"""


from random import uniform
from math import sqrt

def random_throw(radius):
    random_x = uniform(-radius, radius)
    random_y = uniform(-radius, radius)
    
    if sqrt(random_x**2 + random_y**2) <= radius:
        within_circle = True
    else:
        within_circle = False
    
    return random_x, random_y, within_circle

no_of_throws = 100
count_in_circle = 0

for i in range(no_of_throws):
    
    *_, within_circle = random_throw(1)
    
    if within_circle:
        
        count_in_circle += 1
        
print(f'Pi is approximately equal to: {(4*count_in_circle) /no_of_throws}')