Created
May 21, 2018 15:48
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the analytic density, the asymptotic approximation and the numerical computer-generated approximation for a given exponential distribution
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| N= 5000; | |
| n = 2; | |
| lambda = 1; | |
| mu = 3; | |
| p = ones([n,1]); | |
| x = zeros(n,1); | |
| e = zeros(n,1); | |
| y = zeros(n,1); | |
| for i =1:N; | |
| x(:,i) = exprnd(lambda,n,1); | |
| e(:,i) = x(:,i) - lambda*p; | |
| y(:,i) = mu*p + e(:,i); | |
| munhat = mean(y); | |
| wn = sqrt(n)*(munhat - mu); | |
| end | |
| anlytcwn = inv(gamma(n)*lambda.^n)*sqrt(n)*((sqrt(n)*(wn + sqrt(n)*lambda)).^(n-1)).*(exp(-(sqrt(n)/lambda)*(wn + sqrt(n)*lambda))); | |
| asympwn = normpdf(wn,0, lambda.^2); | |
| draws = wn; | |
| %draws = anlytcwn; | |
| %draws = asympwn; | |
| gridsze = 300; | |
| lowbd = min(draws); | |
| upbd = max(draws); | |
| stderr = std(draws); | |
| interquart = prctile(draws,75) - prctile(draws,25); | |
| A = min(stderr,(interquart/1.34)); | |
| h = .9*A*(length(draws)^(-1/5)); | |
| dom = linspace(lowbd,upbd,gridsze)'; | |
| ran = zeros(gridsze,1); | |
| for i = 1:gridsze; | |
| a = -.5*sign( abs( (draws - dom(i,1))/h ) -sqrt(5) ) + .5; | |
| draws2 = nonzeros( draws.*a ); | |
| tempp = zeros(length(draws2),1); | |
| for j = 1:length(draws2); | |
| tempp(j,1) = (.75/sqrt(5))*(1 -.2*( (draws2(j) - dom(i,1))/h )^2); | |
| end; | |
| ran(i,1) = (1/( (length(draws)*h) ) )*sum(tempp); | |
| end; | |
| plot(dom, ran) | |
| hold on; | |
| plot(wn, asympwn) | |
| hold on; | |
| plot(wn, anlytcwn) |
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the code is in Octave