Created
November 20, 2014 22:50
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VPN Shared Secret decoder for networkConnect files
It seems the clear text string's length needs to be a multiple of 12. Filling the remaining characters with null bytes worked for me.
#!/usr/bin/python
import sys
import base64
cleartext = sys.argv[1]
while len(cleartext) % 12 != 0:
cleartext += chr(0x00)
decryption_key = [0x7d, 0x89, 0x52, 0x23, 0xd2, 0xbc, 0xdd, 0xea, 0xa3, 0xb9, 0x1f]
i = 0
cryptotext = ""
for ch in cleartext:
b = ord(ch) ^ decryption_key[i]
cryptotext += chr(b)
i += 1
i = i % len(decryption_key)
result = base64.b64encode(cryptotext)
print("Shared Secret: %s" %(result))
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Inspired by your code, and given the fact that if A ^ B = C, then C ^ B = A, or C ^ A = B. I wrote the following code attempting to generate the crypto text. However, I only get similar crypto code. It seems Apple put some rand data at the tail of the crypto text. So do you have idea how to generate exactly the same crypto code? Thanks.