Created
August 24, 2016 22:28
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Python implementation of anagram solver
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from collections import defaultdict | |
import string | |
words = open("enable1.txt").read().splitlines() | |
print(max(len(x) for x in words)) | |
def add(a, b): | |
return tuple(x+y for x, y in zip(a, b)) | |
def over(a, b): | |
return any(x>y for x, y in zip(a, b)) | |
def counts(word): | |
count = [0]*27 | |
for c in word.lower(): | |
if not c.islower(): | |
continue | |
count[ord(c)-ord('a')] += 1 | |
return tuple(count) | |
anagrams = defaultdict(list) | |
by_len = defaultdict(list) | |
for word in words: | |
if len(word) <= 3: | |
continue | |
count = counts(word) | |
anagrams[count].append(word) | |
by_len[sum(count)].append(count) | |
def print_all(sentence, sofar): | |
if not sentence: | |
print(' '.join(sofar)) | |
return | |
for word in anagrams[sentence[0]]: | |
print_all(sentence[1:], sofar + [word]) | |
def recurse(target, left, curr, sentence): | |
if curr == target: | |
print_all(sentence, []) | |
return | |
for n in range(left, 0, -1): | |
for count in by_len[n]: | |
new = add(curr, count) | |
if over(new, target): | |
continue | |
recurse(target, left-n, new, sentence + [count]) | |
req = 'Help, someone stole my purse' | |
count = counts(req) | |
from datetime import datetime | |
a = datetime.now() | |
recurse(count, sum(count), tuple([0]*27), []) | |
b = datetime.now() | |
print(b-a) |
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