Created
May 30, 2012 23:48
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Do a recursive get over the keys of nested dictionaries
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# I always have problems with the names, please help me :) | |
def rget(dictionary, *args): | |
'''Recursive `.get()` function. | |
Do a recursive get over the keys of nested dictionaries. | |
>>> things = {'a': {'b': {'c': 'd'}}} | |
>>> rget(things, 'a', 'b', 'c') | |
'd' | |
>>> rget(things, 'a', 'b') | |
{'c': 'd'} | |
>>> rget(things, 'a') | |
{'b': {'c': 'd'}} | |
>>> rget(things, 'a', 'b', 'c', 'd') | |
>>> rget(things, 'fake_key') | |
>>> rget(things, 'a', 'fake_key') | |
''' | |
to_be_returned = None | |
if args[1:]: | |
to_be_returned = rget(dictionary.get(args[0]), *args[1:]) | |
elif args[0:] and isinstance(dictionary, dict): | |
to_be_returned = dictionary.get(args[0]) | |
return to_be_returned |
The doctest example variable?
If you want it to return None if it can't find the key or if it tries to access a keys of something that's not a dict, I'd just put the reduce in a try block.
FTR because we've already talked about this by chat.
This is exactly what I'm trying to avoid, the need of use try-except blocks or nested ifs.
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What's "things"?