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main.md

Frontier Physics Paper

Statement

$$ \ds{f}{t}=0 $$

Proof

Let $f=mx+c$, where $m$, $x$, and $c$ are real. Then $\ds{f}{t}=\ds{\left(mx\right)}{t}+\ds{c}{t}=0$. q.e.d.

Raw
myst.yml
version: 1
project:
math:
# Note the 'single quotes'
'\mat': '\mathbf{#1}'
'\ds': '\frac{d #1 }{d #2 }'
site:
template: book-theme
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