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Strange Set Behaviour in Apex
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Integer nCallsToEquals = 0; | |
public class HashingTest { | |
private String s; | |
public HashingTest(HashingTest ht) { | |
this.s = ht.s; | |
} | |
public HashingTest(String s) { | |
this.s = s; | |
} | |
public Integer hashCode() { | |
return s.hashCode(); | |
} | |
public Boolean equals(Object o) { | |
++nCallsToEquals; | |
if(o instanceof HashingTest) { | |
return s == ((HashingTest)o).s; | |
} else { | |
return false; | |
} | |
} | |
} | |
HashingTest k1 = new HashingTest('a'); | |
HashingTest k2 = new HashingTest('b'); | |
System.debug('k1.hashCode(): ' + k1.hashCode()); | |
System.debug('k2.hashCode(): ' + k2.hashCode()); | |
Set<HashingTest> aSet = new Set<HashingTest>(); | |
aSet.add(k1); | |
aSet.add(k2); | |
nCallsToEquals = 0; | |
aSet.contains(k1); | |
System.debug('nCallsToEquals: ' + nCallsToEquals); | |
System.assertEquals(1, nCallsToEquals); | |
nCallsToEquals = 0; | |
aSet.contains(k2); | |
System.debug('nCallsToEquals: ' + nCallsToEquals); | |
System.assertEquals(1, nCallsToEquals); | |
// Comment out this debug line to get expected number of calls to equals() | |
System.debug('aSet: ' + aSet); | |
nCallsToEquals = 0; | |
aSet.contains(k1); | |
System.debug('nCallsToEquals: ' + nCallsToEquals); | |
System.assertEquals(1, nCallsToEquals); | |
nCallsToEquals = 0; | |
aSet.contains(k2); | |
System.debug('nCallsToEquals: ' + nCallsToEquals); | |
System.assertEquals(1, nCallsToEquals); |
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