Created
December 8, 2017 18:13
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find median of two sorted arrays
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| const median = (A = [], B = []) => { | |
| const m = A.length; | |
| const n = B.length; | |
| let iMin = 0; | |
| let iMax = m; | |
| let halfLength = Math.floor((m + n + 1) / 2); | |
| let result = -1; | |
| console.log('******* START ******'); | |
| console.log('A', A); | |
| console.log('B', B); | |
| console.log('halfLength', halfLength); | |
| while (iMin <= iMax) { | |
| console.log('---- LOOP ----'); | |
| console.log('iMin', iMin); | |
| console.log('iMax', iMax); | |
| let i = Math.floor((iMin + iMax) / 2); | |
| let j = halfLength - i; | |
| console.log('i', i); | |
| console.log('j', j); | |
| if (i < m && B[j-1] > A[i]) { | |
| // if the pointer i is less than the length of array A | |
| // and the value of B[j-1] is greater than | |
| // A[i] | |
| iMin = i + 1; | |
| } else if (i > 0 && A[i-1] > B[j]) { | |
| iMax= i - 1; | |
| } else { | |
| let maxOfLeft; | |
| let minOfRight; | |
| if (i === 0) { | |
| maxOfLeft = B[j-1]; | |
| } else if (j === 0) { | |
| maxOfLeft = A[i-1]; | |
| } else { | |
| maxOfLeft = Math.max(A[i-1], B[j-1]); | |
| } | |
| if ((m + n) % 2 === 1) { | |
| result = maxOfLeft; | |
| break; | |
| } | |
| if (i === m) { | |
| minOfRight = B[j]; | |
| } else if (j === n) { | |
| minOfRight = A[i]; | |
| } else { | |
| minOfRight = Math.min(A[i], B[j]); | |
| } | |
| result = Math.floor((maxOfLeft + minOfRight) / 2); | |
| break; | |
| } | |
| } |
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