Jose Gerald akosijose

/*************************************************** Adafruit MQTT Library ESP8266 Example

Must use ESP8266 Arduino from: https://github.com/esp8266/Arduino

Works great with Adafruit's Huzzah ESP board & Feather ----> https://www.adafruit.com/product/2471 ----> https://www.adafruit.com/products/2821

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	/// <summary>
	/// Calculates the SHA-256 hash of a string.
	/// </summary>
	/// <param name="inputString">String to be hashed.</param>
	/// <returns>A SHA-256 string.</returns>

	public static string GetSHA256String(string inputString) {

	StringBuilder result = new StringBuilder();

	questions = ["You went to a party last night and when you arrived to school the next day, everybody is talking about something you didn't do. What will you do?",
	"What quality do you excel the most?",
	"You are walking down the street when you see an old lady trying to cross, what will you do?",
	"You had a very difficult day at school, you will maintain a attitude",
	"You are at a party and a friend of yours comes over and offers you a drink, what do you do?",
	"You just started in a new school, you will...",
	"In a typical Friday, you would like to..",
	"Your relationship with your parents is..."]

	letter_a = []

	# final sender mail

	import smtplib

	def send_email(subject, body):
	server = smtplib.SMTP(host='smtp-mail.outlook.com', port=587)
	server.ehlo()
	server.starttls()
	server.login('[email protected]', 'Sm@rtd00rb3ll@345*')
	message = f'Subject: {subject}\n\n{body}'

	<!doctype html>
	<html>

	<head>
	<title>Glass Calculator</title>
	<link rel="stylesheet" type="text/css" href="style.css">
	</head>

	<body>
	<div class="container">

	```
	Your task is to convert a number into a string that contains raindrop sounds corresponding to certain potential factors. A factor is a number that evenly divides into another number, leaving no remainder. The simplest way to test if a one number is a factor of another is to use the modulo operation.
	The rules of raindrops are that if a given number:
	has 3 as a factor, add 'Pling' to the result.
	has 5 as a factor, add 'Plang' to the result.
	has 7 as a factor, add 'Plong' to the result.
	does not have any of 3, 5, or 7 as a factor, the result should be the digits of the number.
	Examples
	28 has 7 as a factor, but not 3 or 5, so the result would be "Plong".
	30 has both 3 and 5 as factors, but not 7, so the result would be "PlingPlang".

	#payroll

	def computepay(h,r):

	if h > 40:
	p = 1.5 * r * (h - 40) + (40 *r)
	else:
	p = h * r
	return p