Created
August 13, 2017 21:28
-
-
Save alecdoconnor/faddeb2db1a2840a74820b6f23bb0828 to your computer and use it in GitHub Desktop.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
from Crypto.PublicKey import RSA | |
# pem = open('private.pem','r').read() | |
# key = RSA.importKey(pem) | |
# cyphertext = open('message.bin','r').read() | |
# print key.decrypt(cyphertext) | |
def gcd(a,b): | |
if b > a: | |
temp = b | |
b = a | |
a = temp | |
if b == 0: | |
#success | |
return a | |
if b == 1: | |
return 1 | |
return gcd(a%b, b) | |
def egcd(a, b): | |
if a == 0: | |
return (b, 0, 1) | |
else: | |
g, y, x = egcd(b % a, a) | |
return (g, x - (b // a) * y, y) | |
def modinv(a, m): | |
gcd, x, y = egcd(a, m) | |
if gcd != 1: | |
return None # modular inverse does not exist | |
else: | |
return x % m | |
for i in range(1,101): | |
pem = open('../%d.pem' % i,'r').read() | |
cyphertext = open('../%d.bin' % i,'r').read() | |
n = long(RSA.importKey(pem).n) | |
e = long(RSA.importKey(pem).e) | |
for j in range(1,101): | |
if i == j: | |
continue | |
pem2 = open('../%d.pem' % j,'r').read() | |
n2 = long(RSA.importKey(pem2).n) | |
modulus = gcd(n,n2) | |
if modulus != 1: | |
p = long(modulus) | |
q = long(n/modulus) | |
phi = (p-1)*(q-1) | |
d = modinv(e, phi) #(1/e)%phi | |
pem3 = RSA.construct((n,e,d)) | |
print pem3.decrypt(cyphertext) | |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
There are not as many weak RSA keys available as the bug that was causing a faulty number generator on some systems has long since been patched. But it was only a few years ago that many keypairs across the Internet were vulnerable to this simple script.