[Python] Fitting plane/surface to a set of data points

README.md

Python version of the MATLAB code in this Stack Overflow post: http://stackoverflow.com/a/18648210/97160

The example shows how to determine the best-fit plane/surface (1st or higher order polynomial) over a set of three-dimensional points.

Implemented in Python + NumPy + SciPy + matplotlib.

curve_fitting.py

#!/usr/bin/evn python

import numpy as np
import scipy.linalg
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt

# some 3-dim points
mean = np.array([0.0,0.0,0.0])
cov = np.array([[1.0,-0.5,0.8], [-0.5,1.1,0.0], [0.8,0.0,1.0]])
data = np.random.multivariate_normal(mean, cov, 50)

# regular grid covering the domain of the data
X,Y = np.meshgrid(np.arange(-3.0, 3.0, 0.5), np.arange(-3.0, 3.0, 0.5))
XX = X.flatten()
YY = Y.flatten()

order = 1    # 1: linear, 2: quadratic
if order == 1:
    # best-fit linear plane
    A = np.c_[data[:,0], data[:,1], np.ones(data.shape[0])]
    C,_,_,_ = scipy.linalg.lstsq(A, data[:,2])    # coefficients
    
    # evaluate it on grid
    Z = C[0]*X + C[1]*Y + C[2]
    
    # or expressed using matrix/vector product
    #Z = np.dot(np.c_[XX, YY, np.ones(XX.shape)], C).reshape(X.shape)

elif order == 2:
    # best-fit quadratic curve
    A = np.c_[np.ones(data.shape[0]), data[:,:2], np.prod(data[:,:2], axis=1), data[:,:2]**2]
    C,_,_,_ = scipy.linalg.lstsq(A, data[:,2])
    
    # evaluate it on a grid
    Z = np.dot(np.c_[np.ones(XX.shape), XX, YY, XX*YY, XX**2, YY**2], C).reshape(X.shape)

# plot points and fitted surface
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.plot_surface(X, Y, Z, rstride=1, cstride=1, alpha=0.2)
ax.scatter(data[:,0], data[:,1], data[:,2], c='r', s=50)
plt.xlabel('X')
plt.ylabel('Y')
ax.set_zlabel('Z')
ax.axis('equal')
ax.axis('tight')
plt.show()

elif order == 3:
A = np.c_[np.ones(data.shape[0]), data[:,:2], data[:,0]**2, np.prod(data[:,:2], axis=1),
data[:,1]**2, data[:,0]**3, np.prod(np.c_[data[:,0]**2,data[:,1]],axis=1),
np.prod(np.c_[data[:,0],data[:,1]**2],axis=1), data[:,2]**3]

I think the last term should be data[:,1]**3].

Thanks. fixed