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@alexstorer
Created December 21, 2012 16:14
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Parse some XML
from lxml import etree
import re
import csv
import os.path as op
import sys
import glob
class NLRPParse(object):
def __init__(self,fname):
prefix = op.splitext(op.basename(fname))[0]
loc = op.split(fname)[0]
f = open(fname,'r')
tree = etree.parse(f)
fw = open(op.join(loc,prefix+'.csv'),'w')
allcolumns = []
allrows = tree.xpath('//row')
# just get the column names from the first row
# ASSUMES THEY ARE THE SAME FOR EACH ROW!
for col in allrows[0]:
allcolumns.append(col.tag)
self.dw = csv.DictWriter(fw,allcolumns)
self.dw.writeheader()
allrows = tree.xpath('//row')
for r in allrows:
d = dict()
for col in r:
if col.text is not None:
bettertext = re.sub('\r','',col.text)
bettertext = re.sub('\n','',bettertext)
d[col.tag] = bettertext.strip().encode('utf-8')
else:
d[col.tag] = ""
self.dw.writerow(d)
f.close()
fw.close()
for a in glob.glob(sys.argv[1]):
suffix = op.splitext(op.basename(a))[1]
if suffix=='.xml':
print "Parsing file: ", a
p = NLRPParse(a)
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