Edge cases when learning about 'search' functions within array operations

searchEdgeCases.js

/* 
 * =============================================
 * =========== SEARCH EDGE CASES =============== 
 * =============================================
*/

// NOT IN LIST

const listOfDogs =  ["pomeranian", "shih tzu"];

const isCorgiInList = (listOfDogs) => {            
	var searchFor = "corgi"
	for (var i = 0; i < dogs.length; i++) { 
		const currentDog = dogs[i]
	    if (currentDog === searchFor) {
	        return true
	    }
	}
	return false
}

isCorgiInList(listOfDogs) // false

// NOT IN LIST

const listOfDogs =  ["pomeranian", "shih tzu"];

const isCorgiInList = (listOfDogs) => {            
	var searchFor = "corgi"
	for (var i = 0; i < dogs.length; i++) { 
		const currentDog = dogs[i]
	    if (currentDog === searchFor) {
	        return true
	    }
	}
}

isCorgiInList(listOfDogs) // undefined

// point here: we need to be careful when writing functions to make sure
// we're returning what we intend at the edge case. Do we want to make
// the function return false or undefined if we're searching for an item
// and it's not in the list? Depends on what we're doing.


// MULTIPLE IN LIST

const listOfDogs =  ["pomeranian", "corgi", "shih tzu", "corgi"];

const isCorgiInList = (listOfDogs) => {            
	var searchFor = "corgi"
	for (var i = 0; i < dogs.length; i++) { 
		const currentDog = dogs[i] 
	    if (currentDog === searchFor) {
	        return true
	    }
	}
	return false
}

isCorgiInList(listOfDogs) // true