Created
October 7, 2022 12:07
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equidistant sampling on a spline
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| import numpy as np | |
| import napari | |
| from scipy.interpolate import splprep, splev | |
| n = 10 | |
| w = np.linspace(0, 8*np.pi, num=n) | |
| x = [0, 1, 1, 1,] | |
| y = [0, 0, 10, 10] | |
| z = [0, 0, 0, 100] | |
| xyz = np.stack((x, y, z), axis=-1) | |
| # calculate spline representation of curve | |
| tck, _ = splprep([*xyz.T], s=0, k=3) | |
| # sample points on spline | |
| n_points_spline = 100 | |
| u = np.linspace(0, 1, n_points_spline) | |
| sampled_points = splev(u, tck) | |
| sampled_points = np.stack(sampled_points, axis=-1) | |
| inter_point_differences = np.diff(sampled_points, axis=0) | |
| inter_point_distances = np.linalg.norm(inter_point_differences, axis=-1) | |
| cumulative_distance = np.cumsum(inter_point_distances) | |
| cumulative_distance /= cumulative_distance[-1] | |
| # compute spline coefficients for normalised cumulative distance | |
| tck_prime, _ = splprep([np.linspace(0, 1, num=len(cumulative_distance))], u=cumulative_distance, s=0, k=3) | |
| equidistant_u = splev(u, tck_prime) | |
| equidistant_point_samples = splev(equidistant_u, tck) | |
| equidistant_point_samples = np.stack(equidistant_point_samples, axis=-1).squeeze(axis=0) | |
| viewer = napari.Viewer(ndisplay=3) | |
| viewer.add_points(xyz) | |
| viewer.add_points(sampled_points) | |
| viewer.add_points(equidistant_point_samples) | |
| napari.run() |
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