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| // https://leetcode.com/problems/binary-search-tree-iterator | |
| /** | |
| * Definition for a binary tree node. | |
| * type TreeNode struct { | |
| * Val int | |
| * Left *TreeNode | |
| * Right *TreeNode | |
| * } | |
| */ | |
| type BSTIterator struct { | |
| stack []*TreeNode | |
| } | |
| func Constructor(root *TreeNode) BSTIterator { | |
| iterator := BSTIterator{ | |
| stack: []*TreeNode{}, | |
| } | |
| iterator.walkToMin(root) | |
| return iterator | |
| } | |
| // Next returns the next smallest number | |
| func (i *BSTIterator) Next() int { | |
| value := -1 | |
| stackSize := len(i.stack) | |
| if stackSize > 0 { | |
| current := i.stack[stackSize - 1] | |
| i.stack = i.stack[:stackSize - 1] | |
| value = current.Val | |
| i.walkToMin(current.Right) | |
| } | |
| return value | |
| } | |
| // HasNext tells whether we have a next smallest number or not | |
| func (i *BSTIterator) HasNext() bool { | |
| return len(i.stack) > 0 | |
| } | |
| // walkToMin walks to the minimum element of the given subtree | |
| func (i *BSTIterator) walkToMin(root *TreeNode) { | |
| for root != nil { | |
| i.stack = append(i.stack, root) | |
| root = root.Left | |
| } | |
| } |
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