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Swift encrypt/decrypt string using XOR
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import Foundation | |
extension Character { | |
func utf8() -> UInt8 { | |
let utf8 = String(self).utf8 | |
return utf8[utf8.startIndex] | |
} | |
} | |
func encrypt(c:Character, key:Character) -> String { | |
let byte = [c.utf8() ^ key.utf8()] | |
return String(bytes: byte, encoding: NSUTF8StringEncoding)! // forced unwrapping alert! | |
} | |
func encrypt(message:String, #key:String) -> String { | |
return reduce(Zip2(message, key), "") { $0 + encrypt($1) } | |
} | |
let message = "Hello world!" | |
let secretKey = "(:.,?P!9@PAz" // really should be randomly generated! | |
let encryptedMessage = encrypt(message, key: secretKey) // > "`_B@PpVV2<%[" | |
let decryptedMessage = encrypt(encryptedMessage, key: secretKey) // > "Hello world!" |
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/* (Requires Swift 1.2) | |
In the version above you'll notice that there's use of forced Optional unwrapping. | |
This is potentially hazardous. Here's a version that deals with Optional values safely. | |
Having to 'reduce' Optional Strings adds significant complexity. | |
Below, I've shown 2 ways of dealing with this (Monadic bind & 'if let' syntax). | |
*/ | |
import Foundation | |
// Monadic bind for Optionals | |
infix operator >>= {associativity left} | |
func >>= <A,B> (m: A?, f: A -> B?) -> B? { | |
if let x = m {return f(x)} | |
return .None | |
} | |
extension Character { | |
func utf8() -> UInt8 { | |
let utf8 = String(self).utf8 | |
return utf8[utf8.startIndex] | |
} | |
} | |
func encrypt(key:Character, c:Character) -> String? { | |
let byte = [key.utf8() ^ c.utf8()] | |
return String(bytes: byte, encoding: NSUTF8StringEncoding) | |
} | |
// Curried func for convenient use with map | |
func encryptKey(key:String)(message:String) -> String? { | |
return reduce(zip(key, message), Optional("")) { str, c in str >>= { s in encrypt(c).map {s + $0} }} | |
} | |
let message = "Hello world!" | |
let secretKey = "(:.,?P!9@PAz" // really should be randomly generated! | |
let encryptedMessage = encryptKey(secretKey)(message: message) // > .Some("`_B@PpVV2<%[") | |
// As the encryptKey func is curried it can be passed directly to map | |
let decryptedMessage = encryptedMessage.map(encryptKey(secretKey)) // > .Some("Hello world!") | |
/* here's how the encrypt function would look like using 'if let' syntax | |
func encryptKey_if_let(key:String)(message:String) -> String? { | |
return reduce(zip(key, message), Optional("")) { if let str = $0, c = encrypt($1) { | |
return str + c | |
} else { | |
return .None} | |
} | |
} | |
*/ |
My message is just a string object when returned from the server. How come I cannot call .map on a string? Sorry, I'm still relatively new to Swift. The only difference I see between your code and mine is that your string is an optional String.
I'm wondering if there's a library around this solution or was this dropped back then?
Thanks :)
Shai
could someone explain encryptKey? I'm guessing that its reducing zipped tuples of the key and message characters. However it looks like its calling the encrypt function with a tuple, instead of 2 characters. Can/How could this work in Swift 3?
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This started as a Twitter conversation with https://twitter.com/sketchyTech and resulted in the following blog post: http://sketchytech.blogspot.co.uk/2014/10/bytes-for-beginners-xor-encryption-and.html
The idea was to show a simple way of using XOR to encrypt a string in Swift. The version presented here does essentially the same thing, though written in a functional style.
Using Swift it's possible to access a UTF8 representation of a
String
, but not aCharacter
, therefore an extension has been added to make this possible. I'd consider the most interesting implementation detail of this gist to be the use ofZip2
. It initialises astruct
from twoSequenceType
s and allows the two sequences to be iterated simultaneously as pairs. In this casereduce
iterates through the twoString
s as tuple values(Character, Character)
. Eachtuple
is passed toencrypt(s:Character, key:Character) -> String
which returns an encryptedString
that is then appended to the previous result.For more details about the use of XOR take a look at the linked blog post above.