Created
November 22, 2011 05:23
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Ruby Golf
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# Written against Ruby 1.9.2 | |
# Hole #1: FizzBuzz | |
# I accidentally saw Cyrus's solution before trying my own, so no attempt | |
# Hole #2: Caesar Cipher | |
# Works only for `[a-zA-Z]*` | |
def caesar(f,x) | |
f.each_char.map{|c|t=c.ord+x;(t-1)&31>25&&t+=x<0?26:-26;t.chr}*'' | |
end | |
# Hole #3: String Counter | |
def count(f,s) | |
f.scan(/#{Regexp.quote(s)}/i).size | |
end | |
# Hole #4: Rock-Paper-Scissors | |
# Anyone know why I can't remove the space before the first `?`? | |
def play(f) | |
m=%w(Rock Paper Scissors);c,h=rand(3),m.index(f);m[c]+','+(h==c ?'Draw':(!h||h!=(c+1)%3?'Lose':'Win')) | |
end | |
# Hole #5: Swingers | |
# For a trivial (non-random) solution, remove `s.shuffle!;` | |
def swingers(s) | |
s.shuffle!;x,y=s.transpose;y<<y.shift;s.each{|t|t[1]=y.shift} | |
end | |
puts caesar("hello", 3) | |
puts caesar("khoor", -3) | |
puts caesar("abcxyz", 1) | |
puts caesar("abcxyz", -1) | |
puts count("banana", "a") | |
puts count("RubySource provides advice, tutorials, commentary, and insight into the Ruby and Rails ecosystem","ruby") | |
puts swingers([["Homer","Marge"],["Micky","Minnie"],["Fred","Wilma"],["Peter","Lois"],["George","Judy"]]).inspect | |
puts play("Rock") | |
puts play("Paper") | |
puts play("Scissors") | |
puts play("Soap") |
Oh, you're right! Welp, one mystery solved. Even nicer work - mine aren't as tight!
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I had trouble with the ternary operators as well re: your comment on L18. I believe the interpreter is looking for a variable/function called
c?
at that point since?
s are valid chars for those. Nice work! Mine are here.