Created
March 19, 2016 11:10
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The confidence sort in pure Python (from Reddit's codebase)
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# Rewritten code from /r2/r2/lib/db/_sorts.pyx | |
from math import sqrt | |
def _confidence(ups, downs): | |
n = ups + downs | |
if n == 0: | |
return 0 | |
z = 1.281551565545 | |
p = float(ups) / n | |
left = p + 1/(2*n)*z*z | |
right = z*sqrt(p*(1-p)/n + z*z/(4*n*n)) | |
under = 1+1/n*z*z | |
return (left - right) / under | |
def confidence(ups, downs): | |
if ups + downs == 0: | |
return 0 | |
else: | |
return _confidence(ups, downs) |
In python2 x/y is integer division, so line #13 and #15 will be incorrect.
Easily fixed by moving the z*z to the left of the division.
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this is double work; because
already does that.
you should remove
confidence
and rename_confidence
toconfidence
see my fork for a better understanding: https://gist.github.com/jay-bricksoft/fdd3797b1443153389d34a4b5280ac54
cheers