Created
January 30, 2012 16:58
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Polygon
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using namespace std; | |
#include <algorithm> | |
#include <iostream> | |
#include <iterator> | |
#include <numeric> | |
#include <sstream> | |
#include <fstream> | |
#include <cassert> | |
#include <climits> | |
#include <cstdlib> | |
#include <cstring> | |
#include <string> | |
#include <cstdio> | |
#include <vector> | |
#include <cmath> | |
#include <queue> | |
#include <deque> | |
#include <stack> | |
#include <list> | |
#include <map> | |
#include <set> | |
////////////// Prewritten code follows. Look down for solution. //////////////// | |
#define foreach(x, v) for (typeof (v).begin() x=(v).begin(); x !=(v).end(); ++x) | |
#define For(i, a, b) for (int i=(a); i<(b); ++i) | |
#define D(x) cout << #x " is " << (x) << endl | |
const double EPS = 1e-6; | |
int cmp(double x, double y = 0, double tol = EPS) { | |
return (x <= y + tol) ? (x + tol < y) ? -1 : 0 : 1; | |
} | |
////////////////////////// Solution starts below. ////////////////////////////// | |
const double pi = 2 * acos(0); | |
struct point{ | |
double x, y; | |
point (double x, double y) : x(x), y(y){} | |
point (){} | |
}; | |
point center (const point &p, const point &q, const point &r){ | |
double ax = q.x - p.x; | |
double ay = q.y - p.y; | |
double bx = r.x - p.x; | |
double by = r.y - p.y; | |
double d = ax * by - bx * ay; | |
if (cmp (d, 0) == 0){ | |
puts("Collinear"); | |
assert(false); | |
} | |
double cx = (q.x + p.x) / 2.0; | |
double cy = (q.y + p.y) / 2.0; | |
double dx = (r.x + p.x) / 2.0; | |
double dy = (r.y + p.y) / 2.0; | |
double t1 = bx * dx + by * dy; | |
double t2 = ax * cx + ay * cy; | |
double x = (by * t2 - ay * t1) / d; | |
double y = (ax * t1 - bx * t2) / d; | |
return point(x, y); | |
} | |
point operator - (const point &p, const point &q){ | |
point ans (p.x - q.x, p.y - q.y); | |
return ans; | |
} | |
bool operator == (const point &p, const point &q){ | |
return (cmp (p.x, q.x) == 0 and cmp(p.y, q.y) == 0); | |
} | |
int main(){ | |
double x1, y1, x2, y2, x3, y3; | |
while (scanf("%lf %lf %lf %lf %lf %lf", &x1, &y1, &x2, &y2, &x3, &y3) == 6){ | |
point p(x1, y1); point q(x2, y2); point r(x3, y3); | |
point c = center(p, q, r); | |
p = p - c; | |
q = q - c; | |
r = r - c; | |
double radius = sqrt(p.x * p.x + p.y * p.y); | |
double theta = atan2(p.y, p.x); | |
bool found = false; | |
for (int v = 3; v <= 1000; v++){ | |
bool sp, sq, sr; | |
sp = sq = sr = false; | |
for (int k = 0; k < v; k++){ | |
double alpha = theta + k * 2 * pi / v; | |
double x = radius * cos(alpha); | |
double y = radius * sin(alpha); | |
point t (x , y ); | |
/*if (v == 3){ | |
printf("t = %lf %lf\n", x, y ); | |
printf("p = %lf %lf\n", p.x, p.y ); | |
printf("q = %lf %lf\n", q.x ,q.y); | |
printf("r = %lf %lf\n", r.x , r.y); | |
puts(""); | |
}*/ | |
if (p == t) sp = true; | |
if (q == t) sq = true; | |
if (r == t) sr = true; | |
} | |
//if(v==3){D(sp); D(sq); D(sr);} | |
if (sp and sq and sr){ found = true; printf("%d\n", v); break;} | |
} | |
assert(found); | |
/*printf("Point: (%lf,%lf)\n", p.x, p.y); | |
printf("Point: (%lf,%lf)\n", q.x, q.y); | |
printf("Point: (%lf,%lf)\n", r.x, r.y);*/ | |
} | |
return 0; | |
} |
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