Last active
June 4, 2020 19:50
-
-
Save angeloped/51b333bb02abbbda0063ba365938fb06 to your computer and use it in GitHub Desktop.
A simple Fibonacci sequence solver.
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
''' | |
written by: Bryan Angelo | |
''' | |
def fibCount(nth=0,ntp=0,sus=False): # where / limit / yield | |
# infinite loop | |
A,B = 1,1 | |
nth_ = 0 | |
while 1: | |
if bool(nth): # last number of specific iteration limit | |
if nth_ == nth: | |
yield B | |
elif bool(ntp): # return iteration count and nearest number reached | |
if B >= ntp: | |
yield (nth_, B) | |
elif bool(sus): # continuous computation | |
yield B | |
X = A + B | |
A = B | |
B = X | |
nth_ += 1 | |
def isFibonacci(n): | |
# A utility function that returns true if x is perfect square | |
def isPerfectSquare(x): | |
s = None if x < 0 else x**0.5 | |
# Returns true if n is a Fibinacci Number, else false | |
return s*s == x | |
# n is Fibinacci if one of 5*n*n + 4 or 5*n*n - 4 or both is a perferct square | |
return isPerfectSquare(5*n*n + 4) or isPerfectSquare(5*n*n - 4) | |
if __name__ == "__main__": | |
import time | |
print(isFibonacci(5)) # determine if fibonacci number | |
time.sleep(1) | |
print(next(fibCount(nth=10))) # last number of specific iteration limit | |
time.sleep(1) | |
print(next(fibCount(ntp=10))) # return iteration count and nearest number reached | |
time.sleep(1) | |
for i in fibCount(sus=True): # continuous computation | |
print(i) | |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment