Mario Colina angulo4
Cython-dot
/ Control Flow | Coding_Challenges_1.py
Created
February 2, 2020 17:13
Python 3 | Control Flow
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| """ | |
| Create a function named same_name() that has two parameters named your_name and my_name. | |
| If our names are identical, return True. Otherwise, return False. | |
| """ | |
| # Write your same_name function here: | |
| def same_name(your_name, my_name): |
natzir
/ cannibalization.ipynb
Last active
November 24, 2023 14:47
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natzir
/ SERP-analysis.ipynb
Created
October 7, 2019 14:22
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MichelleDalalJian
/ py4e_ex_09_04
Created
October 7, 2017 14:43
9.4 Write a program to read through the mbox-short.txt and figure out who has the sent the greatest number of mail messages. The program looks for 'From ' lines and takes the second word of those lines as the person who sent the mail. The program creates a Python dictionary that maps the sender's mail address to a count of the number of times th…
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| fname = input("Enter file:") | |
| if len(fname) < 1 : name = "mbox-short.txt" | |
| hand = open(fname) | |
| lst = list() | |
| for line in hand: | |
| if not line.startswith("From:"): continue | |
| line = line.split() | |
| lst.append(line[1]) |
MichelleDalalJian
/ py4e_ex_08_05
Created
October 7, 2017 12:54
8.5 Open the file mbox-short.txt and read it line by line. When you find a line that starts with 'From ' like the following line: From [email protected] Sat Jan 5 09:14:16 2008 You will parse the From line using split() and print out the second word in the line (i.e. the entire address of the person who sent the message). Then print out…
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| fhand = open("mbox-short.txt") | |
| count = 0 | |
| for line in fhand: | |
| line = line.rstrip() | |
| if line == "": continue | |
| words = line.split() | |
| if words[0] !="From": continue | |
| print(words[1]) |