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How to time multiple functions
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from timeit import repeat | |
setup = 'x = ("a", "b", "c", "d"); idx = 2' | |
stmt_range = """ | |
[x[i] for i in range(len(x)) if i != 2] | |
""" | |
stmt_slice = """ | |
list(x[:2] + x[3:]) | |
""" | |
stmt_pop = """ | |
l = list(x) | |
l.pop(idx) | |
""" | |
stmt_del = """ | |
l = list(x) | |
del l[idx] | |
""" | |
codes = [ | |
(stmt_range, "range"), # 0 | |
(stmt_slice, "slice"), # 1 | |
(stmt_pop, "pop"), # 2 | |
(stmt_del, "del"), # 3 | |
] | |
for code in codes: | |
print(code[1], end=" ") | |
print(min(repeat(stmt=code[0], setup=setup, number=10**5))) |
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