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April 8, 2018 00:45
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Show that for three real number that satisfy 0 < x < y < z < π/2 , the following inequality holds: (x+y) sin(z) + (x-z) sin(y) < (y+z) sin(x)
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import math | |
import random | |
count = 0 | |
n = 1000000 #montecarlo simulation | |
for i in range (1000000): | |
z = float(random.uniform(0,(math.pi)/2)) #uniform distribution, it gives a random real number between (0, π/2) | |
y = float(random.uniform(0,z)) | |
x = float(random.uniform(0,y)) | |
side_1 = float((x+y) * math.sin(z) + (x-z) * math.sin(y)) | |
side_2 = float((y+z) * math.sin(x)) | |
if side_1 < side_2 : # inequality we want to prove | |
count = count + 1 # every time the inequality has proved, we add 1 to the variable "count" | |
print('The inequality has been true:', count, 'times') | |
print() | |
if count == n: # condition in order to prove the inequality | |
print (' "n" and "count" are equal so the inequality is almost certainly true') | |
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