Check if string is palindrome if 1 or 2 characters can be removed from anywhere

palindromeCheck.js

const handlePrintAfterCharRemoval = (result, char) => {
    switch (result) {
        case 'palindrome': return char;
        case 'not possible': return result;
        default : 
            if (result.length === 1) {
                return `${result}${char}`;
            }
            return ''; // implies that function should continue to try other ways to check the plaindrome
    }
}
function PalindromeCreator(str, index = 0, misMatchStr = '') { 

  // code goes here
  const strLen = str.length - index - 1;
  let revisedMisMatchStr = misMatchStr;
  const currChar = str[index];
  const reverseChar = str[strLen];
  const reachedHalfWay = Math.round(str.length / 2) === index;
  if (currChar !== reverseChar) {
    const removeCurrChar = str.slice(0, index) + str.slice(index + 1, str.length);
    const resultAfterCurrCharRemoval = handlePrintAfterCharRemoval(PalindromeCreator(removeCurrChar), currChar);
    if (resultAfterCurrCharRemoval) {
        return resultAfterCurrCharRemoval;
    }
    const removeLastChar = str.slice(0, strLen) + str.slice(strLen + 1, str.length);
    const resultAfterLastCharRemoval = handlePrintAfterCharRemoval(PalindromeCreator(removeCurrChar), reverseChar);
    if (resultAfterLastCharRemoval) {
        return resultAfterCurrCharRemoval;
    }
    revisedMisMatchStr += `${currChar}${reverseChar}`;
  }
  if (revisedMisMatchStr.length > 2) {
    return 'not possible';
  }
  if (reachedHalfWay) {
    return misMatchStr ? misMatchStr : 'palindrome';
  }
  return PalindromeCreator(str, index + 1, revisedMisMatchStr);
}